Question

Length of rectangle is three times bigger than the width. Area of rectangle is 27. A) find width of rectangle B) find length of rectangle C) find perimeter of rectangle.

What is the answer? I need help to solve it.

Answer 1

Answer:

Length: 9

Width: 3

Perimeter: 24

Step-by-step explanation:

First you can set up a few equations. You know that L x W is your area, or 27.

L * W = 27

Then you also know that your length is equal to three times the width.

L = 3W

So you can substitute L into the first equation to solve for W.

3W * W = 27

3W^2 = 27

W^2 = 9

W = 3

Then you can plug 3 into either equation to solve for your length.

L = 3(3)

L = 9

Then your perimeter is just 2L + 2W

2(9) + 2(3) = 24

Answer 2

Answer:

Step-by-step explanation:

Let the dimensions of the rectangle be length = L and width = W. Then P = perimeter = 2L + 2W.  A = area of rectangle = L * W.  Finally, L = 3W.

Here A = 27 units^2 = W*(3W) = (3*W^2), or 3W^2 = 27 units^2, or

W^2 = 9 units^2, or W = 3 units.  Then L = 3W = 3(3 units) = 9 units.

The length of the rectangle is 9 units.  See above.

The perimeter of the rectangle is 2(9 units) + 2(3 units) = 24 units.