Question

A sample of diborane gas has a pressure of 345 torr at a temperature of -15c and volume of 3.48L if conditions are changed so that the temperature is 36c and the pressure is 468 torr what will be the volume of the sample

Answer 1

Answer: 3.05L= V2

Explanation:

using

P1V1/T1=P2V2/T2

where p1= 345torr

T1, tempertaure= -15c+ 273=258K

T2, temperature= 36+ 273=309K

p2, Pressure= 468 torr

V2=???

P1V1/T1=P2V2/T2

v2=P1V1T2/T1P2= 345X3.46L X 309/ 258X 468=

V2=  3.05L