Question

An amusement park has two types of season passes. Plan 1 charges a one-time fee of $170.00 for admission plus $8.00 every trip for parking. Plan 2 charges a one-time fee of $93.00 for parking plus $15.00 every trip for admission. For what number of trips is the cost of these plans the same?

Answer 1

Answer:

Plan1:

y = 170 + 8x

Plan2:

y = 93 + 15x

170 + 8x  = 93 + 15x

7x = 77

x = 11 Trips

Step-by-step explanation:

Answer 2

The number of trips when the cost of plan 1 and plan 2  would cost the same amount of money is 11 trips.

When the plans cost the same amount of money?

The equation that reprepsents the total cost of both plans is:

Total cost = one time fee + (cost of parking x number of trips)

Plan 1 : 170 + 8t

Plan 2: 93 + 15t

When both plans cost the same, the two above equations would be equal.

170 + 8t  = 93 + 15t

In order to determine the value of t, take the following steps:

Combine similar terms

170 - 93 = 15t - 8t

Add similar terms

77 = 7t

Divide both sides by 7

t = 77/7

t = 11 trips

To learn when two plans would cost the same, please check: https://brainly.com/question/25711114