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How many 4-digit multiples of 5 are there?

please have a formula and don't just write them all out. Thanks.

Respuesta :

Answer:

First 4-digit multiple of 5 is 1000. It is the least 4-digit number and it is multiple of 5.

Last 4-digit number is 9999 which is not a multiple of 5 and so are 9998, 9997, 9996. Largest 4-digit number which is multiple of 5 is 9995.

Number of 4-digit multiples of 5  = 9995 − 1000 /5 + 1 = 8995/ 5 + 1 = 1799 + 1 = 1800

Step-by-step explanation:

A number  x  is said to be a multiple of number  n  if  n  divides the number  x

. One important observation is if  x  is a multiple of  n  then the next multiple of  n  is  x + n

. Hence the multiples of number  n  occur in differences of  n

Suppose  x  and  y  are multiples of  n

. Number of multiples of  n  between  x  and  y

including them is given by  y − x  / n + 1

Because for every n numbers in between  x  and  y  there is a multiple of  n

Combination helps to know the number of ways objects can be arranged. The 4-digit numbers that are multiples of 5 are 1800.

What is a combination?

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

[tex]^nC_r = \dfrac{n!}{r!(n-r)!}[/tex]

where,

n is the number of choices available,

r is the choices to be made.

In order to make a 4 digit number divisible by five the number must end with either 5 or 0, and for the number to be a 4 digit number, it can not start with 0. therefore, the first place can be occupied by any number from 1 to 9, the second place can be occupied by any number from 0 to 9, the third number can be occupied by any number from 0 to 9, and the fourth number can be occupied by any number from 0 or 5. Thus, the possible options are,

[tex]= ^9C_1 \times ^{10}C_1 \times ^{10}C_1 \times ^2C_1\\\\= 9 \times 10 \times 10 \times 2\\\\= 1800[/tex]

Hence, the 4-digit numbers that are multiples of 5 are 1800.

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