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17-05-2020
Mathematics

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simplify [tex]\sqrt{.49x^{18} }[/tex] where x<0

Respuesta :

profarouk profarouk

17-05-2020

Answer:

-7x⁹

Step-by-step explanation:

[tex]\sqrt{49x^{18}} = \sqrt{(7^2)(x^9)^2} =\sqrt{(7x^{9})^2} = |7x^9|[/tex]

Since x < 0 ,then |7x⁹| = -7x⁹

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