Question

What is the simplest radical form of
(x-5)^2=98 ?

please help!!!!​

Answer 1

Answer: $x=7\sqrt{2}+5$

Step-by-step explanation:

$(x-5)^2=98$

Extract the square root on both sides.

$\sqrt{(x-5)^2}=\sqrt{98}$

$x-5=\sqrt{98}$

Add 5

$x=\sqrt{98}+5$

Simplify the square root.

To do this, find numbers that multiply 98 and repeat so that they can be taken out of the root.

7*7*2 or $7^2*2$

Replacing this in the root will make a 7 come out of it.

$x=\sqrt{7^2*2}+5$

$x=7\sqrt{2}+5$