Answer:
Step-by-step explanation:
There are many methods but I give you the factorisation:
[tex]4x^{2} +7x+6= 4x^{2} + 8x - x - 2 +8= (4x^{2} + 8x )- (x + 2) +8\\= 4x(x+2)-(x+2) -8\\=(x+2)(4x-1) +8[/tex]
So
[tex]\frac{4x^{2} +7x+6}{x+2}=\frac{(x+2)(4x-1)+8}{x+2} =\frac{(x+2)(4x-1)}{x+2}+\frac{8}{x+2}\\ \\=4x-1 +\frac{8}{x+2}[/tex]
That means the quotient is 4x-1 and the remainder is 8.
