Question

Which function is the result of vertically shrinking ƒ(x) = (x + 1)2 by a factor of 1∕6?
Question 6 options:

A) ƒ(x) = (6x + 1)2

B) ƒ(x) = (1∕6x + 1)2

C) ƒ(x) = 6(x + 1)2

D) ƒ(x) = 1∕6 (x + 1)2

Answer 1

Answer:

$y=\frac{1}{6}(x+1)^2$ is the result of vertically shrinking

Step-by-step explanation:

Vertical stretch or shrink

$y=c \cdot f(x)$

a stretch by a factor of c if  c>1

a shrink by a factor of c if c<1

c is the factor

We are given that factor = 1/6 <1

So, Vertical shrink

So, $y = \frac{1}{6} \cdot f(x)$

We are given that $f(x) = (x + 1)^2$

So,$y=\frac{1}{6}(x+1)^2$

Option D is true

Hence $y=\frac{1}{6}(x+1)^2$ is the result of vertically shrinking

Answer 2

Answer:

ƒ(x) = (1∕6x + 1)^2

Step-by-step explanation: