Question

A large brine tank containing a solution of salt and water is being diluted with fresh water. The relationship between the elapsed time, t. in hours, after the dilution begins and the concentration of salt in the tank, S(t) in grams per liter (g / 1) , is modeled by the following function S(t) = 500e ^ (- 0.25t) What will the concentration of salt be after 10 hours? Round your answerif necessary to the nearest hundredth

Answer 1

Answer:

41.04

Step-by-step explanation:

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Answer 2

the concentration of salt be after 10 hours is 14.04 grams per liter

Given :

The relationship between the elapsed time, t. in hours, after the dilution begins and the concentration of salt in the tank is given by

$S(t)=500e^{^{\:}\left(-\:0.25\cdot t\right)\:}$

here 't' is the time taken . and S(t) is the concentration of salt.

We need to find the concentration of salt S(t) after 10 hours

So , we need to find S(10)

Replace 't'  with 10 in the given equation

$S(t)=500e^{^{\:}\left(-\:0.25\cdot t\right)\:}\\S(10)=500e^{^{\:}\left(-\:0.25\cdot 10\right)\:}\\S(10)=41.04$

the concentration of salt be after 10 hours is 14.04 grams per liter

Learn more : brainly.com/question/16415326