Answer:A and B
Step-by-step explanation:
x^2+3x-18=0
The two numbers which their product is -18 and their sum is 3 are +6 and -3
Therefore we remove 3x from the equation and replace with +6x-3x
x^2+6x-3x-18=0
We Factorise
x(x+6)-3(x+6)=0
Factorise again
(x+6)(x-3)=0
Equate (x+6) and (x-3) to be equal to zero separately
x+6=0 or x-3=0
x=-6 or x=3
