select two values of x that are roots of this equation (picture included)
x^2+2x-5=0
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The roots of the equation will be - 1 - √6 and - 1 + √6. Then the correct options are B and D.
The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.
The quadratic equation is given below.
x² + 2x - 5 = 0
The solution of the quadratic equation will be
x² + 2x - 5 = 0
Add 1 on both sides, then the equation will be
x² + 2x + 1 - 5 = 1
x² + 2x + 1 = 1 + 5
(x + 1)² = 6
Taking square root on both sides, then the equation will be
x + 1 = ±√6
x = - 1 ±√6
Then the roots of the equation will be - 1 - √6 and - 1 + √6.
Then the correct options are B and D.
More about the solution of the equation link is given below.
https://brainly.com/question/545403
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