Respuesta :

Answer:

The center is at (3,1) and the radius is [tex]\sqrt{8}[/tex]

Step-by-step explanation:

I am going to assume you meant to write

[tex](x-3)^2+(y-1)^2 = 8[/tex]

Since if both variables were x it would not be a circle:

Then you can find the center and radius using the general formula of a circle:

[tex](x-h)^2 + (y-k)^2 = r^2[/tex]

where the center is at (h,k) and r is the radius

Therefore:

The center is at (3,1) and the radius is [tex]\sqrt{8}[/tex]

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