Question

In the following exercise you will be given a wild type (ancestral) DNA code that you will transcribe and translate into an amino acid sequence (remember start codons). In addition to the wild type code, you have been given five mutated sequences of the wild type code that you will also transcribe and translate. For each mutation you will determine the mutation type (substitution, insertion, deletion) and effect (silent, nonsense, missense, frameshift-missense, frameshift-nonsense) by comparing to the wild type. Wild type template strand:
3'TGTACTTCAAACCGATT5"
mRNA-
AA Seq.

Answer 1

Answer:

Wild type template strand

3'TGTACTTCAAACCGATT5'

Wild type template DNA strand after transcription give following mRNA sequence

5’ACAUGAAGUUUGGCUAA3’

This mRNA has five codons; out of five, four codons (AUG, AAG, UUU and GGC)encode aminoacid and one is stop codon (UAA). Therefore, after translation this mRNA gives following amino acid sequence

Methionine-Lysine-Phenylalanine-Glycine