Respuesta :

Hi..... Please, follow me, step by step...

[tex]\dfrac{2m}{5}+3=7(4m-3)\\ \dfrac{2m+5.3=5.7(4m-3)}{\not 5}\rightarrow 2m+5.3=5.7(4m-3)\rightarrow\\ 2m+15=35(4m-3)\rightarrow 2m+15=140m-105\rightarrow\\ 15+105=140m-2m\rightarrow 138m=120\rightarrow (2.3.23)m=2.2.2.3.5\rightarrow\\ m=\dfrac{\not 2.\not 3.\,23}{\not 2.\,2.\,2.\not 3.\,5}\rightarrow \boxed{m=\dfrac{23}{20}}[/tex]

Thank you for your trust... :)
[tex](2m)/(5)+3=7(4m-3)[/tex] 

[tex]2m+15=35(4m-3)[/tex] 

[tex]2m+15=140m-105[/tex] 

[tex]15=140m-105-2m[/tex] 

[tex]15=138m-105[/tex] 

[tex]15+105=138m[/tex] 

[tex]120=138m[/tex] 

[tex]120/138=m [/tex] 

[tex]20/23=m[/tex] 

[tex]m=20/23[/tex] 

Decimal Form: 0.8696
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