Question

Find all real values of x such that f (x) = 0.
$f(x) = \frac{-6x - 9}{2}$

Answer 1

Plug in f(x) = 0

0 = (-6x - 9)/2

Multiply 2 on both sides

0 = -6x - 9

Add 9 on both sides

9 = -6x

Divide -6 on both sides

x = 9/-6 = -3/2

When x = -3/2, f(x) = 0

Answer 2

Plug in f(x) = 0 to solve 

$f(x) = \frac{-6x-9}{2}$

$0 = (-6x - 9)/2$

$0 = -6x - 9$

$9 = -6x$

$x = 9/-6 = -3/2$

$x = -3/2, f(x) = 0$