Question

A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular circuit?
A. 4.8 V
B. 387 A
C. 387 V
D. 4.8 A

Answer 1

voltage = current × resistance

plug in all the numbers

voltage = 9 × 43

now simplify

voltage = 387 V = C.

Answer 2

Answer : The correct option is, (C) 387 V

Solution : Given,

Electric current = 9 A

Resistance = 43 ohms

Using ohm's law,

$V=I\times R$

V = applied voltage

I = electric current

R = resistance

Now put all the given values in this formula, we get the value of applied voltage.

$V=(9A)\times (43\Omega)=387V$

Therefore, the applied voltage in the circuit will be, 387 V