Question

what is the ph of a solution with [oh-] = 2.6 × 10^-3 m?

Answer 1

pOH = - log [ OH⁻]

pOH = - log [ 2.6x10⁻³]

pOH = 2.58

pH + pOH = 14

pH + 2.58 = 14

pH = 14 - 2.58

pH = 11.42