Question

cotx(tanx-1)=0

solve over [0, 2pie)

Answer 1

$cot x (tan x - 1) = 0$ 


$cot x tan x - cot x = 0$ 

$= cot x = 1/tan x = cot x tan x = 1$ 

$1 - cot x = 0$ 

$1 = cot x$

$x = arccot 1$

= [0,2π) 

x = π/4 and x=5π/4