Question

An inequality is shown below: −np − 6 ≤ 3(c − 5) Which of the following solves for n?

Answer 1

Answer:

 $\Rightarrow n\geq\frac{9-3c}{p}$

Step-by-step explanation:

We have been given the inequality

−np − 6 ≤ 3(c − 5)

We will solve for n

So, firstly we will shift 6 on right hand side of the inequality we get:

$-np\leq3(c-5)+6$

Now, we will open the parenthesis on right hand side of the inequality;

$-np\leq3c-15+6$

$-np\leq3c-9$

$-n\leq\frac{3c-9}{p}$

$\Rightarrow n\geq\frac{9-3c}{p}$