Question

find the perimeter of rectangle qrst whose vertices are q(–2, 2), r(1, 0), s(0, –1), and t(–3, 1). a. 5.02 units b. 5.09 units c. 7.29 units d. 10.04 units

Answer 1

Perimeter of a rectangle = 2(l + w)
Length = $\sqrt{(1+2)^2+(0-2)^2} = \sqrt{3^2+(-2)^2} = \sqrt{9+4} = \sqrt{13}=3.61$
Width = $\sqrt{(0-1)^2+(-1-0)^2} = \sqrt{(-1)^2+(-1)^2} = \sqrt{1+1} = \sqrt{2}=1.41$

Perimeter = 2(3.61 + 1.41) = 2 x 5.02 = 10.04 units

Answer 2

Answer:

D: 10.04 units

Step-by-step explanation:

Short to what is written above