Question

What are the vertical asymptotes of the function f(x) = the quantity of 4 x plus 8, all over x squared plus 3 x minus 4?

Answer 1

$f(x)=\dfrac{4x+8}{x^2+3x-4}\\\\The\ domain:x^2+3x-4\neq0\\\\x^2+4x-x-4\neq0\\\\x(x+4)-1(x+4)\neq0\\\\(x+4)(x-1)\neq0\iff x\neq-4\ \wedge\ x\neq1$

$The\ vertical\ asymptotes\ of\ the\ function\ f:\ \boxed{x=-4\ and\ x=1}$