Question

Iodine chloride, ICl, can be made by the following reaction between iodine, I2, potassium iodate, KIO3, and hydrochloric acid.

2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O

Calculate how many grams of iodine are needed to prepare 28.6 grams of ICl by this reaction.

Answer 1

The balanced chemical reaction is:

2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O 

We are given the amount of the product to be produced from the reaction. This will be the starting point of our calculations.

28.6 g ICl (1 mol / 162.35 g ICl ) ( 2 mol I2 / 5 mol ICl ) ( 253.81 g I2 / 1 mol I2 ) = 17.88 g I2

Answer 2

The number of 28.6 grams of ICl by this reaction is 17.88 g12.

Calculation of a number of grams of iodine:

The balanced chemical reaction is:

2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O

here is the amount of the product to be produced from the reaction.

So,

28.6 g ICl (1 mol / 162.35 g ICl ) ( 2 mol I2 / 5 mol ICl ) ( 253.81 g I2 / 1 mol I2 ) = 17.88 g I2

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