Answer:
The sampling distribution is, p = center = 0.043
The standard deviation of the sample, s = 6.0015×10⁻⁴
The shape is normal
Step-by-step explanation:
Here we have the standard deviation of a sample proportion, given by the following relation;
[tex]Standard \ deviation \ of\ \hat p = \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.043 \times (1-0.043)}{114250} } = 6.0015 \times 10^{-4}[/tex]
The center = p = 4.3% or 0.043
The shape is found by the value of n×p hence;
114250 × 0.043 = 4912.75 > 10 and
n(1 - p) = 114250 × (1 - 0.043) = 109337.25 also > 10 hence the shape is normal.