Question

In 1998 French teams and kind that was 1034 m long imagine two charges +2.0nC and -2.8nC at the opposite ends of the kite calculate the magnitude of the electric force between them

Answer 1

Answer:

$F=4.71\times 10^{-14}\ N$            

Explanation:

We have,

Charges of +2.0nC and -2.8nC are placed at the opposite ends of the kite. The distance between them is 1034 m. It is required to find the magnitude of the electric force between them. The formula of the electric force is given by :

$F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 2\times 10^{-9}\times 2.8\times 10^{-9}}{(1034)^2}\\\\F=4.71\times 10^{-14}\ N$

So, the magnitude of electric force between them is $4.71\times 10^{-14}\ N$ and the force is attractive in nature.