Respuesta :
Answer:
Option A is correct.
Because two molecules of NO are consumed per molecule of O2, the rate of disappearance of O2(g) is 2.5×10−5 Ms−1.
Explanation:
2NO(g) + O2(g) → 2NO2(g)
The rate of a chemical reaction is defined as the amount of reactant used up or the amount of products formed in the reaction.
From the chemical balance, 2 moles of NO gives 1 mole of O2, hence, it is evident that 2 molecules of NO is consumed per 1 molecule of O2.
Hence, the rate of consumption of O2 is exactly half of the rate of consumption of NO.
Rate of consumption of O2 = (1/2) × Rate of consumption of NO = (1/2) × 5.0×10−5 Ms−1
= (2.5×10−5) Ms−1
Hope this Helps!!!
The rate of disappearance of oxygen under the same conditions is [tex]\bold {2.5x10^-^5 Ms^-^1}[/tex] because two molecules of NO are consumed per molecule of oxygen.
The given chemical reaction is,
[tex]\bold{2NO(g) + O_2(g) \rightarrow 2NO_2(g)}[/tex]
The rate of disappearance of NO molecule = [tex]\bold { 5.0x10^-^5 Ms^-^1}[/tex]
In the reaction, 2 moles of NO react with one molecule of Oxygen molecule to form 2 moles of Nitrogen dioxide.
Hence, only half of the oxygen is needed to complete the reaction.
The rate of oxygen consumption = half of the NO consumption.
[tex]\bold {= \dfrac{ 5.0x10^-^5 Ms^-^1} {2}}\\\\\bold {= (2.5x10^-^5) Ms^-^1}[/tex]
Therefore, the rate of disappearance of Oxygen is [tex]\bold {2.5x10^-^5 Ms^-^1}[/tex]
To know more about the rate of reaction, refer to the link:
https://brainly.com/question/3334857