Respuesta :
I showed how to determine these with your calculator on a different question of your's.
a)
.1879 or 18.8%
b)
.2742 or 27.4%
The percent of young women who have cholesterol levels greater than 219 is 19.2% and the percent of young women who have cholesterol levels between 192 and 220 is 29.6%.
Given :
The cholesterol levels of a group of young women at a university are normally distributed, with a mean of 188 and a standard deviation of 35.
a) First determine the z value at (x = 219).
[tex]\rm z =\dfrac{x-\mu}{\sigma}[/tex]
[tex]\rm z =\dfrac{219-185}{39}=0.87[/tex]
So, the percent of young women who have cholesterol levels greater than 219 is:
50 - 30.8 = 19.2%
b) First determine the z value at (x = 192).
[tex]\rm z_{192} =\dfrac{192-185}{39}=0.17[/tex]
Now, determine the z value at (x = 220).
[tex]\rm z_{220} =\dfrac{220-185}{39}=0.89[/tex]
So, the percent of young women who have cholesterol levels between 192 and 220 is:
= 34.8 - 5.2 = 29.6%
For more information, refer to the link given below:
https://brainly.com/question/795909