Question

A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is replaced before the second marble is drawn, what is P(blue second | green first)? If the first marble is not replaced before the second marble is drawn, what is P(blue second | green first)?

Answer 1

Answer:

see below

Step-by-step explanation:

4 blue and 6 green = 10 marbles

P(green) = 6green/ 10 total = 6/10 = 3/5

replace the marble

4 blue and 6 green = 10 marbles

P(blue) = 4 blue/ 10 total =4/10 = 2/5

P (green, replace, blue ) = 3/5*2/5 = 6/25

4 blue and 6 green = 10 marbles

P(green) = 6green/ 10 total = 6/10 = 3/5

do not replace the marble

4 blue and 5 green = 9 marbles

P(blue) = 4 blue/ 9 total =4/9

P (green,  do not replace, blue ) = 3/5*4/9 = 4/15