Question

A 0.600 g sample of a compound of arsenic and oxygen was found to
contain 0.454 g of arsenic. What is the empirical formula of the
compound? *

A. AsO2
B. As2O
C. As2O3
D. AsO

Answer 1

Answer:

The answer is C. As2O3

Explanation:

0.600 gr of Arsenic and Oxygen.

0.454 gr of Arsenic

So, 0.146 gr of Oxygen will be in the compound.

- First: The grams of each element must be divided by its atomic weight:

• 0.454 gr As / 74.92u As = 0.00606

• 0.146 gr O / 16u O = 0.009125

- Both results must be divided by the lowest number found:

• 0.00606 / 0.00606 = 1 As

• 0.009125 / 0.00606 = 1.5 O

- As one of the values ​​is not an integer then both results are multiplied until both give an integer:

• 1 As * 2 = 2 As

• 1.5 O * 2 = 3 O

- Then the answer is given:

• As2O3

Answer 2

The empirical formula of the compound is As₂O₃

The correct answer to the question is Option C. As₂O₃

From the question given above, the following data were obtained:

• Mass of compound = 0.6 g
• Mass of As = 0.454 g
• Mass of O = 0.6 – 0.454 = 0.146 g
• Empirical formula =?

The empirical formula of the compound can be obtained as follow:

As = 0.454 g

O = 0.146 g

Divide by their molar mass

As = 0.454 / 75 = 0.006

O = 0.146 / 16 = 0.009

Divide by the smallest

As = 0.006 / 0.006 = 1

O = 0.009 / 0.006 = 1.5

Multiply by 2 to express in whole number.

As = 1 × 2 = 2

O = 1.5 × 2 = 3

Thus, the empirical formula of the compound is As₂O₃

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