Question

⦁ A person pulls horizontally with a force of 64 N on a 14-kg box. There is a force of friction between the box and the floor of 36 N. Find the acceleration of the box in m/s2.

Answer 1

Answer:2m/s^2

Explanation:

resultant force=(rf)

Pulling force=F=64N

Frictional force(fr)=36N

Mass(m)=14kg

Acceleration=(a)

rf=F-fr

rf=64-36

rf=28

But resultant force(rf)=massxacceleration

rf=mxa

28=14xa

Divide both sides by 14

28/14=(14xa)/14

2=a

Therefore acceleration=2m/s^2