Answer:9.8x10^(-3) w/m°C
Explanation:
Quantity of heat(Q)=14.1w
Distance(d)=2.44cm=2.44/100=0.0244m
Area(a)=1.88m^2
Temperature change(t)=18.6°C
thermal conductivity(k)=?
K=(Qxd) ➗ (a x t)
K=(14.1x0.0244) ➗ (1.88x18.6)
K=0.34404 ➗ 34.968
K=9.8x10^(-3) w/m°C