Answer: 633.6 g of [tex]CO_2[/tex] can be produced from the decomposition of 4.8 moles of [tex]Fe_2(CO_3)_3[/tex]
Explanation:
The balanced chemical equation for decomposition of [tex]Fe_2(CO_3)_2[/tex] is :
[tex]Fe_2(CO_3)_2\rightarrow Fe_2O_3+3CO_2[/tex]
According to stoichiometry :
1 mole of [tex]Fe_2(CO_3)_2[/tex] produce = 3 moles of [tex]CO_2[/tex]
Thus 4.8 moles of [tex]Fe_2(CO_3)_2[/tex] will rproduce=[tex]\frac{3}{1}\times 4.8=14.4moles[/tex] of [tex]CO_2[/tex]
Mass of [tex]CO_2=moles\times {\text {Molar mass}}=14.4moles\times 44g/mol=633.6g[/tex]
Thus 633.6 g of [tex]CO_2[/tex] can be produced from the decomposition of 4.8 moles of [tex]Fe_2(CO_3)_3[/tex]
