Question

Suppose you want to factor the expression x2+ 2xn+n2. Given that n> 0, what are the factors? Explain.

Answer 1

Answer:

$\left(x+n\right)^2=(x+n)(x+n)$

Step-by-step explanation:

$\:x^2+\:2xn+n^2$

$\mathrm{Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2$

$\left(x+n\right)^2=(x+n)(x+n)$

Answer 2

The factors are (x + n)(x + n)

x² + 2xn + n²

Now let's factor it

x² + 2xn + n²

2xn = xn + xn

Therefore,

x² + xn + xn + n²

x(x + n) + n(x + n)

(x + n)(x + n)

(x + n)²

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