Respuesta :
Answer:
log3 {c/2}
Step-by-step explanation:
Addiing two logs together is equivalent to multiplying their arguments.
Thus,
log3(6c) + log3 1/12 = log3 6*c*[1/12], or log3 ( log3 [6c][1/12] ).
This simplifies to log3 {c/2} because 6c(1/12) = c/2