Respuesta :
So, the time taken is 22 years.
Given that,
A huge ice glacier in the Himalayas has initially covered an area [tex]A_0=45 km^2[/tex]
Given relationship is,
[tex]A=45e^{-0.05t}[/tex]
Also, the area of the glacier decreases to 15 km per square then,
[tex]15=45e^{-0.05t}\\e^{-0.05t}=\frac{1}{3} \\t=\frac{ln\frac{1}{3} }{-0.05} \\t=21.97\\t\approx 22 y[/tex]
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