Question

A circle has a radius of 6/7
units and is centered at (-2.3,0).
Write the equation of this circle.

Answer 1

Answer:

$(x-2.3)^{2} + y^{2} = \frac{36}{49}$

Explanation:

The general formula for the circle center at a point distinct from origin:

$(x - h)^{2}+(y-k)^{2} = r^{2}$

The equation of this circle is:

$(x-2.3)^{2} + y^{2} = \frac{36}{49}$

Answer 2

Answer:

$(x+2.3)^2+y^2=36/49$

Explanation:

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