Question

A 65 kg rock climber has 30,000 J of potential energy. What is the height of the rock climber above the ground?

Answer 1

Answer:47.1meter

Explanation:

potential energy(pe)=30000j

Mass(m)=65kg

Acceleration due to gravity(g) =9.8m/s^2

Height=(pe) ➗ (m x g)

Height=30000 ➗ (65 x 9.8)

Height=30000 ➗ 637

Height=47.1m