Question

If the frequency of an allele ("A") for an STR locus is 0.02 and the frequency of another allele ("B") for the same locus is 0.03, what is the probability that a member of that population is heterozygous ("AB") for the above alleles?

Answer 1

Answer:

Heterozygous (AB) for the STR locus = Allele (A) x allele (B) = 0.02 x 0.03 = 0.0006

Explanation:

The probability of the heterozygous genotype AB is equal to the product of the probabilities of these two independent events (i.e., independent events represented by allele segregation)= 0.02 x 0.03 = 0.0006