The work that need to do is 66.24 J.
Hello guys, before we can count how much the work that needed to pull the toy, we should know how formula to count it first. Because the movement is with the angle, so the formula is :
[tex]\boxed {\bold {W = F \times s \times \cos(\theta)}} [/tex]
If :
We know that :
W = work = ... J
[tex]W = F \times s \times \cos(\theta) \\ W = 7.5 \times 9.2 \times \cos(15) \\ W = 69 \times 0.96 = 66.24 \: J[/tex]
So, the work that need to do is 66.24 J.
Subject : Physics
Class : Junior High School/Senior High School
Keyword : Work; Force; Shift; and Elevation Angle