Question

log2x (2x^2+8x-6) =2

Answer 1

Answer:

$2x^3+8x^2-3x=0$

Step-by-step explanation:

$2x (2x^2+8x-6)=2\\multiply-all-in-bracets-by-2x\\4x^3+16x^2-6x=2\\devide-all-by-2\\2x^3+8x^2-3x=0$