Answer:
There are NO real solutions to this equation as per the study of its discriminant.
Step-by-step explanation:
In order to answer the question, one needs to examine the "discriminant" associated with this quadratic equation.
Recall that the discriminant of a quadratic equation of the form:
[tex]a\,x^2+b\,x+c=0[/tex]
is given by: [tex]b^2-4\, (a)\,(c)[/tex]
in our case : [tex]a=1\, ,\,b=6\,, and\,\,\,c=13[/tex]
Then the discriminant becomes:
[tex]b^2-4\, (a)\,(c)=6^2-4\,(1)\,(13) =36-52=-16[/tex]
The discriminant is then a negative number, which means that there are NO real solutions (its solutions must involve imaginary numbers)
