Answer:
1. The missing value is 9
2. The missing value is 81
Step-by-step explanation:
1. To find the missing value of a perfect square you divide the center term (-6 as is -6x) by two to get 3 then square the three to get 9
To check this write it as the simplified form (x-3)^2 and multiply it out again using foil. x times x is x^2, -3 times x is -3x ( this happens twice adding up to the -6x), and -3 times -3 is 9 making it x^2 -6x +9
2. Follow the steps for the previous problem to get the same answer for this one. Divide 18 (middle term) by 2 making 9. Then square the 9 making 81.
The missing value that makes the polynomial x² - 6x + ? a perfect square quadratic is 9
From the question, we are to determine the value that makes the given polynomial a perfect square.
Recall that,
A quadratic of the form ax² + bx + c is a perfect quadratic if b² = 4ac
The given polynomial is x² - 6x + ?
By comparing, we are to determine the value of c that makes the polynomial a perfect square quadratic.
From the given polynomial,
a = 1
b = -6
c = ?
Putting these into b² = 4ac, we get
(-6)² = 4 × 1 × c
36 = 4c
c = 36 ÷ 4
c = 9
Hence, the missing value that makes the polynomial x² - 6x + ? a perfect square quadratic is 9
Learn more on Making a quadratic a perfect square here: https://brainly.com/question/14584348
