Answer:
1,736.1N
Explanation:
The information we have is:
mass: [tex]m==1,250kg[/tex]
initial velocity: [tex]v_{i}=0[/tex]
final velocity: [tex]v_{f}=50km/h[/tex]
we need to converto to m/s:
[tex]v_{f}=\frac{50km}{h}*\frac{1h}{3,600s} *\frac{1000m}{1km} \\v_{f}=13.89m/s[/tex]
time: [tex]t=10s[/tex].
First we need to calculate the acceleration:
[tex]a=\frac{v_{f}-v_{i}}{t}[/tex]
substituting the values:
[tex]a=\frac{13.89m/s-0}{10s} \\a=1.389m/s^2[/tex]
and now we use Newton's second law to calculate the net force:
[tex]F=ma[/tex]
substituting the mass and acceleration:
[tex]F=(1250kg)(1.389m/s ^2)\\\\F=1,736.1N[/tex]
the net force on the vehicle is in Newtons is: 1,736.1N
