Question

A person dives into the ocean and finds Object A at a depth of 7.4meters. He records the elevation of Object A as -7.4. He finds Object B 5.8 meters deeper than Object A. He finds Object C at 3/4 the depth of Object B. How will the diver record the elevation of Object C?

Answer 1

Answer:

-9.9 meters

Step-by-step explanation:

Object was found at a depth of 7.4 meters and recorded as -7.4 meters.

Object B is found 5.8 meters. Hence, object B was found at a depth of

7.4 + 5.8 = 13.2 meters

and it will be recorded as -13.2 meters.

Object C is found at a depth 3/4 of object B. Hence, object C is found at a depth of

$\frac{3}{4} * 13.2$  = 9.9 meters

and its elevation will be recorded as -9.9 meters.