Answer:
The correct option is;
A. Real, upside-down, and larger than the actual bulb.
Explanation:
Here we have that the blue dot is at the focal point of the mirror which gives the focal point as -12
Therefore, the center of curvature of the concave mirror where assumed to be a spherical mirror is given as follows;
Center of curvature ≈ 2 × Length of focus
That is the location of the center of curvature ≈ -24
Hence the object is between the focus and the center of curvature
When an object is placed in between the focus and the center of curvature of a concave mirror, the image is real, upside-down and magnified.
