Question

A 2-way light bulb for a 110 V lamp has filament that uses power at a rate of 50.0 W. What is the resistance of the filament?

Answer 1

Answer:r=242ohms

Explanation:

Power(p)=50w

Volt(v)=110v

Resistance(r)=?

Power(p)=((volt)^2)/(resistance(r))

50=110^2/r

Cross product

50xr=110^2

50r=12100

r=12100/50

r=242ohms