Question

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Solve the equation for all real solutions in simplest form:
-5c^2+c-18=-6c^2

Answer 1

Answer:

$c=-\frac{1}{2}+\frac{\sqrt[]{73} }{2}$ which is the same as: $c=3.77$

or

$c=-\frac{1}{2}-\frac{\sqrt[]{73} }{2}$ which is the same as: $c=-4.77$

Step-by-step explanation:

$-5c^2+c-18=-6c^2$

Add 6 on both sides.

$-5c^2+c-18+6c^2=-6c^2+6c^2$

$c^2+c-18=0$

a=1

b=1

c=-18

$c=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac} }{2a}$

$c=\frac{-1\frac{+}{}\sqrt[]{(1)^2-4(1)(-18)} }{2(1)}$

$c=\frac{-1\frac{+}{}\sqrt[]{1+72} }{2}$

$c=\frac{-1\frac{+}{}\sqrt[]{73} }{2}$

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$c=-\frac{1}{2}+\frac{\sqrt[]{73} }{2}$

$c=-\frac{1}{2}-\frac{\sqrt[]{73} }{2}$