Question

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Solve the equation for all real solutions in simplest form:
4n^2-19n+18=0

Answer 1

Answer:

n=3.4, n=1.3

Step-by-step explanation:

4n^2-19n+18=0

solve using quadratic formula

a=4, b=-19, c=18

n=-(-19)±√(-19)^2-4·4·18/2·4

(solve using calulator or PEMDAS)

(solve for both + and -)

n=3.4, n=1.3