Respuesta :
Answer:
Explanation:
Just start with the trivial. If gravity was a constant then E = mgh and 1/2 m v^2 = E
so v=sqrt(2gh)=sqrt(2*9.8*1590000) = 5582m/s
Now this will be too high as gravity reduces with distance.
However it is still true that 1/2mv^2 = loss of gravitational potential energy
so 1/2 v^2 = loss of gravitational potential ( i.e a field without considering mass )
As g = GM/ Ro^2 and P = - GM/R
the Po = - 9.8 * (6370*10^3)= - 62.4 * 10 ^ 6 J/kg
P1= Po * 6370/(6370+1590) = - 49.93 * 10 ^ 6 J/kg
find the CHANGE and then from that the velocity
ie v = sqrt(2*( P1 - Po)) = 5094 m/s
Note how it is a bit smaller than the first estimate but not by such a margin that they are unrecognizably different.
Answer:
5001.51 m/s
Explanation:
Gravitation potential of a body in orbit from the center of the earth is given as
Pg = -GM/R
Where G is the gravitational constant 6.67x10^-11 N-m^2kg^-2
M is the mass of the earth = 5.98x10^24 kg
R is the distance from that point to the center of the earth = r + Re
r is the distance above earth surface, Re is the earth's radius.
R = 1590 km + 6370 km = 7960 km
Pg = -(6.67x10^-11 x 5.98x10^24)/7960x10^3
Pg = -50108793.97 J/kg
The negative sign means that the gravitational potential is higher away from earth than it is at the earth's surface (it shows convention).
This indicates the kinetic energy per kilogram that the chest of jewel will fall with to earth.
Gravitation Potential on earth's surface is
Pg = -GM/Re
= -(6.67x10^-11 x 5.98x10^24)/6370x10^3 = -62616326.53 J/kg
Difference in gravity potential = -50108793.97 - (-62616326.53)
= 12507532.56 J/kg
The velocity V of the jewel chest will be
0.5v^2 = 12507532.56
V^2 = 25015065.12
V = 5001.51 m/s