Answer: % = 10.789%
Explanation:
I will give a step by step analysis to make this problem easy to solve.
from our knowledge in conservation of momentum, we know that;
Momentum before impact = Momentum after impact
i.e.
28(m) + 165(-0.39) = 0
where M = - (165*-0.39) / 28
M = 2.298 Kg
from this we have that the initial mass of the gas in the Propulsion is given thus;
= (165 - 146) + 2.298 = 21.298
initial mass = 21.298 Kg
% of gas propellant ejected is given thus = expelled gas / original gas =
% = (2.298 / 21.298) * 100 = 10.789 %
% = 10.789%
cheers i hope this helps!!!!