Respuesta :
Answer:
a) - 0.54
b) No, we expect Andy to lose money each time he plays this game. This game is not a good way to make money.
Step-by-step explanation:
We are told the game costs $2 to play.
In a card game, we have the following:
Total number of cards = 52
Number of number cards (2-10)=36
Number of face cards = 12
Number of ace = 3
Number of ace of clubs = 1
The probability and profits of the game is calculated below.
Probability he gets a number card 2-10 =[tex] \frac{36}{52} = 0.69 [/tex]
Profit = - $2
Probability he gets a face card:
[tex] \frac{12}{52} = 0.23 [/tex]
Profit = $3 - $2 = $1
Probability he gets an ace:
[tex] \frac{3}{52} = 0.06 [/tex]
Profit = $5 - $2 =$3
Probability he gets an ace of clubs:
[tex] \frac{1}{52} = 0.02[/tex]
Profit = $25 - $2 =$23
Andy's expected profit per game wil be given as:
E = probability * profit
= [(0.69 * -2)+(0.23 * 1)+(0.06 * 3)+(0.02 * 23)]
= -0.54
b) No, we expect Andy to lose money each time he plays this game. This game is not a good way to make money.
Andy's expected profit per game (-0.542) is negative, which means he doesn't make any profit per game.
Andy expected profit per game is -0.54.
Andy's expected profit per game (-0.542) is negative, which means he doesn't make any profit per game.
Given that,
The game costs $2 to play.
He draws a card from a deck. If he gets a number card (2-10), he wins nothing.
For any face card ( jack, queen or king), he wins $3. For any ace, he wins $5, and he wins $25 if he draws the ace of clubs.
We have to determine,
Andy's expected profit per game is:
Would you recommend this game to Andy as a good way to make money.
According to the question,
The game costs $2 to play.
Total number of cards = 52
Number of number cards (2 - 10) =36
Number of face cards = 12
Number of ace = 3
Number of ace of clubs = 1
The probability and profits of the game is calculated below.
[tex]Probability \ he \ gets \ a\ number\ card \ 2-10 = \dfrac{36}{52} = 0.69[/tex]
Profit = $2
[tex]Probability\ he \ gets\ a \face\ card= \dfrac{12}{52} = 0.23[/tex]
Profit = $3 - $2 = $1
[tex]Probability\ he \ gets\ an \ace = \dfrac{3}{32 } = 0.06[/tex]
Profit = $5 - $2 =$3
[tex]Probability \ he \ gets \ an\ ace\ of \ clubs: = \dfrac{1}{52} = 0.02[/tex]
Profit = $25 - $2 =$23
Andy's expected profit per game will be given as:
[tex]E = \ Probability \times \ profit\\\\E = [(0.69 \times -2)+(0.23 \times 1)+(0.06 \times 3)+(0.02 \times 23)]\\\\E = -0.54[/tex]
The profit of Andy is -0.54.
- No, Andy to lose money each time he plays this game. This game is not a good way to make money.
Andy's expected profit per game (-0.542) is negative, which means he doesn't make any profit per game.
To know more about Probability click the link given below.
https://brainly.com/question/16102249